36w-w^2-320=0

Solution for 36w-w^2-320=0 equation:

36w-w^2-320=0

We add all the numbers together, and all the variables

-1w^2+36w-320=0

a = -1; b = 36; c = -320;
Δ = b2-4ac
Δ = 362-4·(-1)·(-320)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4}{2*-1}=\frac{-40}{-2}
=+20
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4}{2*-1}=\frac{-32}{-2}
=+16
$